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we have to do angle sum property of triangle
∆CDB
THAN ANGLE A = ANGLE C ( OPPOSITE ANGLES OF A PARALLELOGRAM )
THE SUM OF ADJECENT ANGLES ARE 180° SO ANGLE A + ANGLE B = 180°
WE HAVE TO REPEAT IT WITH ANGLE D ALSO
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A=c= 80
D=c= 100
Step-by-step explanation:
in triangle bdc
angle d +angle B +angle C= 180
..sum of all angles of triangle
45+55+c= 180
c= 180- 100
c= 80
c= A... opposite angle of parallelogram
a= 80
Dc is parallel to ab
db is transversal
d= b = 45 ..... alternate angle
therefore
D = 45+55=.100
and B = 45+55=100
hope it will help you... Try to follow me so that I can help you in next example
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