Math, asked by SeemaJain, 1 year ago

solve 33 , 34 and 35

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Answered by Kundank
2
In question no. 33 we know for some digit B
we are getting B×B = XB (here X can be any digit from 0-9)
So possible Values of B will be
1×1 = 1
5 × 5 = 25
6×6 = 36
B = 0 not possible

So we can easily Find 5 fits perfectly
and Now you can easily Find A which is equals to 4.

In Question No. 34 You can easily Check which option is Correct. The correct option is 1089.


In question No. 35
 \frac{n \times i \times n \times e \times t \times e \times e \times n}{n \times i \times n \times t \times y \times f \times i \times v \times e}  =  \frac{o \times n \times e}{f \times i \times v \times e}
After simplifying we , get
 \frac{e}{y}  = o
E = OY

we know Range of E is 0-10

we are given , option , 3 , 4 ,8 ,2

Case -1
E = 3Y
but we know Y > O
so , y can be (4to10)
But , E ranges from 1-10
so , O does not equal 3

Case - 2

E = 4Y
same condition applied here
So , O does not equal to 4

Case - 3

E = 8Y
same condition Applied here
So , O does not equal to 8

Case - 4

E = 2Y
Now Y Can take possible value of 3 , 4 ,5

So O = 2


Hope it didn't helped you!!


SeemaJain: tnq
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