Question

solve. . . . . . .. ... .... ... .. . . . . ​

Answer 1

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$\sf{7\times11\times13+13}$

Taking 13 common , we get

$\sf{7\times11\times13+13=13 (7\times11+1)}$

13 ( 77 + 1 )

13 ( 78 )

It is a product of two numbers , both greater than 1 . Hence , it is a composite number .

$\sf{7\times6\times5\times4\times3\times2\times1+5}$

taking 5 common , we get

$=\sf{5(7\times6\times4\times3\times2\times1+1)}$

5( 1008 + 1 )

5( 1009 )

It is a product of two numbers , both greater than 1 . So , it is a composite number .