Question

Solve
36 n² - 12an + (a²-b²) = 0​

Answer 1

Answer:

Go through the attachment buddy

Step-by-step explanation:

Hope it helps u

Answer 2

Answer:

n=a+b/6 , n=a-b/6

Step-by-step explanation:

Given that,

36n² - 12an + (a²-b²) = 0

here , a=36 b= -12a c=( a²- b²)

D = b² - 4ac

D = (-12a)² - (4)(36)(a² - b²)

D = 144a² - (144)(a²- b²)

D = 144a² - 144a² + 144b²

D = 144b²

now from quadratic formula

n = -b ± √D / 2a

n = - ( -12a) ±√144b² / 2 x 36

n = 12a ± 12b / 72

• n = 12a + 12b / 72
• n = 12(a + b) / 72
• n = a+ b / 6

also,

• n = 12a - 12b / 72
• n = 12( a -b) /72
• n = a - b / 6