Math, asked by mohitgumber1, 1 year ago

solve 37x +41y =70
41x+37y=86

Answers

Answered by harleen13
103
1st we add both da eq.

37x+41y=70

41x+37y=86

ans. 78x + 78y=156

taking 78 common

78(x+y)=156

x+y=2 --- (1)

sub. both da eq. so sign will be change

37x+41y=70

41x+37y=86

(-) (-) (-) {changing da signs}

ans. -4x+4y= -16

taking -4 common

-4(x-y)=-16

x-y=8 --- (2)



nw frm (1) nd(2)

x+y=2

x-y=8

(add)

ans. 2x=10

so, x=5 nd y= -3
Answered by vartika98765
4

Answer:

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