Question

solve
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Answer 1

Step-by-step explanation:

We have,

$\lim_{x \rarr \infty } \frac{ \sqrt{4 {x}^{2} + 1} - \sqrt{3 {x}^{2} + 1} }{7x - 2}$

$= \lim_{x \rarr \infty } \frac{ x\sqrt{4 + \frac{1}{ {x}^{2} } } - x\sqrt{3 + \frac{1}{ {x}^{2} } } }{x(7- \frac{2}{x}) }$

$= \lim_{x\rarr \infty } \frac{ \sqrt{4 + \frac{1}{ {x}^{2} } } - \sqrt{3 + \frac{1}{ {x}^{2} } } }{(7- \frac{2}{x}) }$

$= \frac{ \sqrt{4 + 0} - \sqrt{3 + 0} }{7 - 0}$

$= \frac{2 - \sqrt{3} }{7}$

Answer 2

Answer:

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