Math, asked by srutec, 10 months ago

solve 3cos²x -2√3 sinx cosx - 3cos²x

Answers

Answered by Disha060

Answer:as per the question given by you, answer should be - root 3 *sin2x

Step-by-step explanation:as 3cos^2x cancels out we are left with root 3*2*sinxcox which is equal to root3*sin2x (by using trigonometric submultiple formula)

Answered by renuthakur3333

Answer:

Expand sin2x=2sinx*cosx

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solve 3cos²x -2√3 sinx cosx - 3cos²x​

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solve 3cos²x -2√3 sinx cosx - 3cos²x