Question

solve
3m^2+2m^2-3m+5
if m=-2​

Answer 1

Answer:

3×(-2)^2+2×(-2)^2-3×-2+5=3×4+2×4+6+5=12+8+6+5=31

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$3( { - 2})^{2} + 2( { - 2})^{2} - 3( - 2) + 5 \\ 12 + 8 + 6 + 5 = 31$