Question

solve:- 3p+2q=12
2p+3q=13
by substitution method?????​

Answer 1

Given equations,

$3p+2q=12\\2p+3q = 13$

Now,

$3p + 2q = 12\\\implies 3p = 12-2q$

$\implies p = \dfrac{12-2q}{3}$

Substituting p in the second equation,

$2(\dfrac{12-2q}{3} ) + 3q = 13$

$\implies \dfrac{24-4q}{3} + 3q = 13$

$\implies 24-4q+9q=39$

$\implies 24 +5q = 39$

$\implies 5q = 39-24$

$\implies 5q = 15$

$\implies \underline{\underline{ q = 3}}$

$\implies p = \dfrac{12-2(3)}{3}$

$\implies p = \dfrac{12-6}{3}$

$\implies \underline{\underline{p = 2}}$

$\boxed{\boxed{\bold{Therefore, \ the \ values \ of \ p \ and \ q \ are \ 2 \ and \ 3 \ respectively.}}}}$

                                                             

Answer 2

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