Question

Solve 3q² + 2q +8 using formule​

Answer 1

Answer:

No real roots are there.

Step-by-step explanation:

b²-4ac=(2)²-4(3)(8)

= 4 -96

= -92

= 4×-23

Quadratic formula = [-b±√(b²-4ac)]/2a

First root is

$\frac{ - 2 + \sqrt{4 \times - 23} }{2 \times 3} \\ = \frac{ - 2 + 2\sqrt{ - 23} }{6} \\ = \frac{ \sqrt{ - 23} - 1}{3}$

Similarly other root is

$= \frac{ - \sqrt{ - 23} - 1 }{3}$

Answer 2

Answer:

hello

Step-by-step explanation:

Roots of quadratic equation...

Roots of quadratic equation...

Roots of quadratic equation...

Roots of quadratic equation... Given equation is,

Roots of quadratic equation... Given equation is,3q

Roots of quadratic equation... Given equation is,3q 2

Roots of quadratic equation... Given equation is,3q 2 =2q+8

Roots of quadratic equation... Given equation is,3q 2 =2q+83q

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=0

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=0

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2,

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2, 3

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2, 3−4

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2, 3−4

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2, 3−4

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2, 3−4 ∴ roots of the given equation are 2,

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2, 3−4 ∴ roots of the given equation are 2, 3

Roots of quadratic equation... Given equation is,3q 2 =2q+83q 2 −2q−8=03q 2 −6q+4q−8=03q(q−2)+4(q−2)=8(3q+4)(q−2)=0∴q=2, 3−4 ∴ roots of the given equation are 2, 3−4

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