solve (3x+1)/16-(x+3)/8=(3x-1)/14-(2x-3)/7
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(3x+1)/16 -(x+3)/8=(3x-1)/14-(2x-3)/7
{(3x+1)-2(x+3)}/16={(3x-1)-2(2x-3)}/14
{3x+1-2x-6}/16={3x-1-4x+6}/14
14{x-5}=16{5-x}
14x-70=80-16x
-70-80=-16x-14x
-150=-30x
x= -150/-30
x= 5
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