Question

solve 3x-1y=3, 4x-8y=64Elimination method.​

Answer 1

3x-1y=3...(1)

4x-8y=64...(2)

Multiply equ (1) by 8

24x-8y=24...(3)

Subtract equ (2) from equ (3)

20x= -40

x= -2

Put x in equ (1)

3(-2)-y=3

-6-y=3

-y=9

y= -9

Hope this helps you

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Answer 2

(eq1)

$3x - y = 3$

(eq2)

$4x - 8y = 64$

Multiplying the first eq. with 8;

(eq3)

$24x - 8y = 24$

Subtracting eq2 and eq3;

*picture*

$x = - \frac{40}{20}$

$x = 2$

x=2

Substituting x=2 in eq1,

$3x - y = 3$

$3(2) - y = 3$

$y = 6 - 3$

$y = 3$

y=3