Question

solve
3x^2-13x-10=0 : x=-2/3

Answer 1

Answer:

Given:

3

x

2

+

13

x

−

10

=

0

Use an AC method to factor the quadratic:

Look for a pair of factors of

A

C

=

3

⋅

10

=

30

with difference

B

=

13

The pair

15

,

2

works.

Use this pair to split the middle term and factor by grouping:

0

=

3

x

2

+

13

x

−

10

0

=

(

3

x

2

+

15

x

)

−

(

2

x

+

10

)

0

=

3

x

(

x

+

5

)

−

2

(

x

+

5

)

0

=

(

3

x

−

2

)

(

x

+

5

)

Hence zeros:

x

=

2

3

and

x

=

−

5

Answer 2

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

X=-2/3

$3 {x}^{2} - 13x - 10 = 0$

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$3 {x}^{2} - 13x - 10 = 0$

$3 {x}^{2} - 10x - 3x - 10 = 0$

$3 {x}^{2} - 3x - 10x - 10 = 0$

$3x(x - 1) + 10(x - 1)$

$(3x + 10)(x - 1)$

put x=-2/3

$3 ( - \frac{2}{3} ) + 10( - \frac{2}{3} - 1)$

$( - \frac{6}{3} + 10) (\frac{ - 2 - 3}{3} )$

$( - 2 + 10)( - \frac{5}{3} )$

$8 \times - \frac{ 5}{3} = - \frac{40}{3}$

Here is your answer..

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