Question

solve : √3x^2-2√2x-2√3=0​

Answer 1

√3 x² - 2√2 x - 2√3 = 0

Multiplying √3 and 2√3 = 6

now, split this in such a way that it's sum of difference will be -2√2

i.e. -3√2 +√2 = -2√2

√3 x²-3√2x +√2x -2√3 =0

=√3x(x -√6) +√2(x -√6) =0

=(x-√6)(√3x +√2) =0

So, (x-√6)=0 or (√3x +√2) =0

x = √6 or x= -√(2/3)= -√6/3