Solve 3x^2-3√6x-20=0 by factorization
Answers
Answered by
0
3x² - 3√6x - 20
3x² - 5√6x + 2√6x - 20
√3x(√3x - 5√2) + 2√2(√3x - 5√2)
(√3x + 2√2)(√3x - 5√2)
3x² - 5√6x + 2√6x - 20
√3x(√3x - 5√2) + 2√2(√3x - 5√2)
(√3x + 2√2)(√3x - 5√2)
Similar questions