Question

Solve 3x^2+ 5 root 5 x - 10=0 by factorization method

Answer 1

$= > 3 {x}^{2} + 5 \sqrt{5} x - 10 = 0 \\ = > 3 {x}^{2} + 3 \sqrt{5} x + 2 \sqrt{5} x - 10 = 0 \\ = > 3x(x + \sqrt{5} ) - 2 \sqrt{5} (x + \sqrt{5} ) = 0 \\ = > (x + \sqrt{5} )(3x - 2 \sqrt{5} ) = 0 \\ = > x + \sqrt{5} = 0 \: or \: 3x - 2 \sqrt{5} = 0 \\ = > x = - \sqrt{5} \: or \: x = \frac{2 \sqrt{5} }{3}$

Answer 2

Given :

$3x^2+ 5 \sqrt5 x - 10=0$

To Find :

Solve $3x^2+ 5 \sqrt5 x - 10=0$ by factorization method

Solution:

Given Equation :$3x^2+ 5 \sqrt5 x - 10=0$

We are supposed to solve by factorization method

$\Rightarrow 3 {x}^{2} + 5 \sqrt{5} x - 10 = 0 \\ \Rightarrow 3 {x}^{2} + 3 \sqrt{5} x + 2 \sqrt{5} x - 10 = 0\\\Rightarrow 3x(x + \sqrt{5} ) - 2 \sqrt{5} (x + \sqrt{5} ) = 0 \\ \Rightarrow (x + \sqrt{5} )(3x - 2 \sqrt{5} ) = 0 \\\Rightarrow x + \sqrt{5} = 0 , 3x - 2 \sqrt{5} = 0 \\ \Rightarrow x = - \sqrt{5} , x = \frac{2 \sqrt{5} }{3}$

Hence The value of x is $-\sqrt{5}$ or$\frac{2 \sqrt{3}}{3}$