solve 3x*2-5x+18 and find zero of tje polynomial
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Answered by
1
just use the formula
x=-b±√b²-4ac/2a
x=-b±√b²-4ac/2a
Answered by
1
D = 25 - 216 = - 196
Since the discriminant is negative so no real roots exist for the given polynomial...
Since the discriminant is negative so no real roots exist for the given polynomial...
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