Math, asked by Vikesh6361, 7 months ago

Solve(3x+2)/7+4(x+1)/5=2(2x+1)/3

Answers

Answered by MrChauhan96
8

\bf\blue{\underline{\boxed{Question}}}

\:

\small\tt{\frac{3x+2}{7}} + {\frac{4(x+1)}{5}}\:=\:{\frac{2(2x+1)}{3}}

\:

\bf\blue{\underline{\boxed{Solution}}}

\:

\small\tt{\frac{\:3x+2}{7}} + {\frac{4(x+1)}{5}}\:=\:{\frac{2(2x+1)}{3}}

\small\tt{\frac{\:3x+2}{7}} + {\frac{4x+4}{5}}\:\:\:\:=\:{\frac{4x+4}{3}}

\:

\small\tt{LCM\:of\:7\:and\:5\:is\:35}

\:

\small\tt{\frac{\:15x+10+28x+28}{35}}\:=\:{\frac{4x+4}{3}}

\small\tt{\:\:3(15x+10+28x+28)\:=\:35(4x+4)}

\small\tt{\:\:3(43x+38)\:=\:35(4x+4)}

\small\tt{\:\:129x+114\:=\:140x+140}

\small\tt{\:\:129x-140x\:=\:140-114}

\small\tt{\:\:-11x\:=\:26}

\small\tt{\:\:x\:=\:{\frac{\:\:\:26}{-11}}}

\small\tt\red{\underline{\boxed{\:\:Answer\rightarrow\:\:x\:=\: - {\frac{26}{11}}}}}

\:

\bf\blue{\underline{\boxed{Hope\:It\: Help\:You}}}

Answered by nidhirandhawa7
0

Step-by-step explanation:

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