solve 3x 2 square -11x-20 =0
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Answered by
12
Answer: (x - 5) ( 3x + 4) = 0
Given :-
☯ 3x² - 11x - 20 = 0
=> 3x² - ( 15 - 4) x - 20 = 0
=> 3x² - 15x + 4x - 20 = 0
=> 3x ( x - 5 ) + 4 ( x - 5) = 0
=> ( x - 5 ) ( 3x + 4) = 0
. ° . either ,
( x - 5) = 0
x = 5
or,
( 3x + 4) = 0
3x = -4
x = -4/3
Answered by
5
3x^2-11x-20
20×3=60
by splitting the middle term
3x^2-15x+4x-20
3x(x-5)+4(x-5)
3x+4=0 ( or ) x-5=0
3x = -4
x = -4/3 or x = 5
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