solve 3x^2 square + 5 x minus 9 is equal to zero give your answer correct to two decimal places
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Answered by
19
Answer:
x ≈ 1.09 or x ≈ -2.75
Explanation:
Compare given Quadratic equation 3x²+5x-9=0 with
ax²+bx+c=0,we get
a=3 , b = 5, c = -9
Discreminant (D) = b²-4ac
= 5²-4×3×(-9)
= 25+ 108
= 133
√D = √133
≈ 11.53
By Quadratic Formula:
x= [-b±√D]/2a
= [-5±11.53]/(2×3)
= (-5±11.53)/6
Therefore,
x=(-5+11.53)/6 or x=(-5-11.53)/6
x = 6.53/6 or x = -16.53/6
x ≈ 1.09 or x ≈ -2.75
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