solve 3x^2 -x-4 by splitting the middle term
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3x^2-x-4=0
3x^2-(4-3)x-4=0
3x^2-4x+3x-4=0
x(3x-4)+1(3x-4)=0
(3x-4)(x+1)=0
3x-4=0 Or x+1=0
x=4/3 Or x=-1
I hope it will help you!!!!!
3x^2-(4-3)x-4=0
3x^2-4x+3x-4=0
x(3x-4)+1(3x-4)=0
(3x-4)(x+1)=0
3x-4=0 Or x+1=0
x=4/3 Or x=-1
I hope it will help you!!!!!
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