Question

solve 3x+2y=11 and 2x-3y=3

Answer 1

Step-by-step explanation:

3x+2y=11

2x-3y =3

by elimination method

3x+2y=11 × (2)

2x-3y =3 × (3)

6x + 4y = 22

6x - 9y = 9

(-) (+) (-)

___________

13y = 23

{ y= 1 }

find the 'x'

3x + 2y =11

3x + 2(1) = 11

3x + 2 = 11

3x = 11 - 2

3x = 9

{x = 3}

verify

2x - 3y = 3

2(3) - 3(1) = 3

6 - 3 = 3

[3 = 3]

Answer 2

Answer:

The answer to the given question is The value of x is 3 and y is 2

Step-by-step explanation:

Given :

3x+2y=11 and 2x-3y=3

To find :

we have to solve this and find the value of x and y.

Solution :

let the two equations

$3x + 2y = 11 - - - (1) \\ 2x - 3y = 3 - - - (2)$

on solving these two equations by an elimination method, we get the value of x and y.

Multiply equation (1) by 3, and the equation becomes

$(3x + 2y = 11)(3) \\ 9x + 6y = 33 - - - (3)$

multiply equation ( 2 ) by 2, and the equation becomes

$(2x - 3y = 3)(2) \\ 4x - 6y = 6 - - - (4)$

Add equations (3) and (4).

$9x+ 6y = 33 \\ 4x - 6y = 6 \\ - - - - - - \\ 13x - 0y = 39$

on Adding, we get the value as

13x=39.

13 multiplying on the left side divides the value on the right side

$x = \frac{39}{13} \\ x = 3$

let us substitute the value of x in equation (2)

$2x - 3y = 3 \\ 2( 3) - 3y = 3$

on further proceedings, we get the value as

$6 - 3y = 3 \\ 6 - 3 = 3y \\ 3 = 3y \\ y = \frac{3}{3} \\ y = 1$

The value of x and y is obtained as 3 and 1 respectively.

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