Math, asked by kgdurge25, 7 months ago

solve 3x+2y=29: 2x-y=18​

Answers

Answered by pritujha1405
0

multiply 5 in equation (1) & 3 in equation (2)

(3x +2y = 29) × 5 --------(1)

(5x -y = 18) × 3-----------(2)

___________

15x +10y = 145

15x -3y = 54

- + -

____________ Now substract

13y =91

y =91/13

y = 7

put the value of y in the equation

3x + 2× 7 =29

3x + 14 = 29

3x = 29 -14

3x = 15

3x = 15/3

X = 5 ANS

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Answered by kopals06
0

Answer:

x = 65/7, y = 4/7

Step-by-step explanation:

This is a simultaneous equation.

We will solve this with substitution.

Let's name the equation 3x + 2y = 29, equation 1.

Let's name the equation 2x + y = 18, equation 2.

In this solution we will solve for x, then afterwards we will substitute the value of x in a equation and find the value for y.

First we will make everything have one variable.

Let's solve equation 2:

2x + y = 18

y = 18 - 2x ( subtract both sides with 2x)

Now let's put this value in equation 1.

3x + 2(2x - 18) = 29

Now that there is no 2nd variable, we will solve this like any other linear equation.

3x + 2(2x - 18) = 29

3x + 4x - 36 = 29

3x + 4x = 29 + 36

7x = 65

x = 65/7

Now that we have the value of x, we can put this in an equation and solve.

3x + 2y = 29

3*(65/7) + 2y = 29

195/7 + 2y = 29

2y = 29 - 195/7

2y = 8/7

y = 8/7 * 1/2

y = 4/7

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