Question

solve 3x+2y-36=0 and 4y-4=60-5x by elimination method​

Answer 1

Answer:

3x+2y-36=0    -----[1]

4y-4=60-5x

4y=60+4-5x

4y=64-5x

5x+4y-64=0    -------[2]

3x+2y-36=0

5x+4y-64=0

(-)  (-)   (+)

-----------------

-2x-2y+28=0

-2x=-28+2y

x=-28+2y  / -2

x=14+2y

sub eqa [1]

3(14+2y)+2y-36=0

42+6y+2y-36=0

42+8y-36=0

8y-36+42=0

8y+8=0

8y=-8

y=-8/8

y=-1

this is my answer