solve (3x+2y)(3x-2y)(9x²+6xy+4y²) (9x²-6xy+4y²)
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Answer:
(3x^2+2y^2)(3y+4)^2(3x-2y)^2
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(3x+2y)(9x^2 -6xy+4y^2)(3x-2y)(9x^2-6xy+4y^2)
=(27x^3+8y^3)(27x^3-8Y^3)
=729x^6 - 64y^6
=(27x^3+8y^3)(27x^3-8Y^3)
=729x^6 - 64y^6
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