Question

Solve 3x+2y-5=0 , 6x-5y-1=0 by substitution method

Answer 1

Answer:

x = 57/42 and y = 10/7

Step-by-step explanation:

3x + 2y - 5 = 0

3x + 2y = 5         (1)

6x - 5y - 1 = 0

6x - 5y = 1           (2)

3x = 5 - 2y

x = (5 - 2y)/3

Put the value of x in equation(1),

3{(5 - 2y)/3} + 2y = 5

15 - 9y + 2y = 5

15 - 7y = 5

-7y = 5 - 15

-7y = -10

y = 10/7

Put the value of y in equation (2),

6x - 5(10/7) = 1

6x - 50/7 = 1

6x = 1 + (50/7)

6x = (7 + 50)/7

6x = 57/7

x = 57/7x6

x = 57/42

I hope this is your answer but I am not 100 percent sure