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3x+2y =7 , 2x+y=4
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3x + 2y = 7............(1)
2x + y = 4...........(2)
From (1)
x = (7 - 2y)/3........(3)
Sunstitute (3) in (2)
2(7 - 2y)/3 + y = 4
[(14 - 4y) + 3y]/3 = 4.............(LCM=3)
14 -4y +3y = 4 × 3
14 - y = 12
Therefore y = 14 -12
= 2
Substute y = 2 in (1)
3x + 2×2 = 7
3x + 4 = 7
3x = 7 - 4
3x = 3
Therefore x = 3/3
= 1
Therefore the values of x = 1 & y = 2
Hope it helps you
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