Question

solve 3x/4-2x+5/3=5/2 and check​

Answer 1

Step-by-step explanation:

$\frac{3x}{4 - 2x} - \frac{2x + 5}{3} = \frac{5}{2 }$

$\frac{3x }{4 - 2x} = \frac{5}{2} - \frac{5}{3}$

$\frac{3x}{4 - 2x} = \frac{5}{6}$

$18x = 5(4 - 2x)$

$18x = 20 - 10x$

$18x + 10x = 20$

$38x = 20$

$x = \frac{20}{38}$

$x = \frac{10}{16}$

$x = \frac{5}{8}$

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Answer 2

Answer:

Required value of x is $2 \frac{7}{24}$

Step-by-step explanation:

Given,

$\frac{3x}{4} + 2x + \frac{5}{3} = \frac{5}{2}$

Separating variable and constant part,

$\frac{3x}{4} + 2x = \frac{5}{2} - \frac{5}{3}$

Adding all variable parts by fraction addition method,

$\frac{3x + 8x}{4} = \frac{5}{2} - \frac{5}{3}$

$\frac{11x}{4} = \frac{5}{2} - \frac{5}{3}$

$\frac{11x}{4} = 5 \times ( \frac{3 - 2}{6} ) = 5 \times \frac{1}{6}$

$\frac{11x}{4} = \frac{5}{6}$

$x = \frac{5}{6} \times \frac{11}{4} = \frac{55}{24} = 2 \frac{7}{24}$

Required value of x is $2 \frac{7}{24}$

Checking part:

Putting x=$2 \frac{7}{24}$

in

$\frac{3x}{4} + 2x + \frac{5}{3}$

So,

$\frac{3}{4} \times \frac{55}{24} + 2 \times \frac{55}{24} + \frac{5}{3} = \frac{5}{2}$