Question

Solve 3x +4y=10 and 5x-2y=8 by substitution method​

Answer 1

Answer:

$x = 2 \\ y = 1$

Step-by-step explanation:

$3x + 4y = 10 \\ 5x - 2y = 8 \\ mulyply \: to \: 2 \: in \: second \: equation \\ 10x - 4y = 16 \\ 3x + 4y = 10 \\ 13x = 26 \\ x = \frac{26}{13} \\ x = 2 \\ put \: the \:value \: of \: x - \\ 3x + 4y = 10 \\ 3 \times 2 + 4y = 10 \\ 6 + 4y = 10 \\ 4y = 10 - 6 \\ y = \frac{4}{4} \\ y = 1$

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Answer 2

Answer:

from 1 we have ,

5x + 2y = 8

x = 8 - 2y

5

now from 2 we have

3 x + 4 y = 10

3( 8-2y)

+ 4 y = 10

5

24-6y+20y

=10

5

24 - 6 y + 4y = 10

5 1

24 - 14 y = 50

14y =50-24

y= 26/14 or

and x =8-2y

5

=8-x(26/14)

5

= 8/1- 26/7

56-26

5

30/7 × 5/1= 150/7

x = 150/7. y = 13/7