solve 3x-5Y+1=0 and 2x+3Y=12 by sublimation method
sivaprasath:
did you meant 'substitution' ?
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2x+3y=12. (1)
3x - 5y +1 = 0
x = (5y -1)/3. (2)
putting value of x in eq. 1
2 × (5y-1)/3 +3y=12
10y -2+9y = 12×3
19y = 38
y=2
putting value of y in eq. (1)
2x +3(2)=12
x= 3
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2
this should be your answer
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