solve ( 3x-5y=16; x-3y=8)
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x-3y=8
x=8+3y_____(1)
3x−5y=16
substitute value of x from (1) in the above equation, we get
3(8+3y)−5y=16
24+9y−5y=16
9y−5y=16−24
4y=−8
y=-8/4
y=−2
Putting value of y in (1) ,we get
x=8+3y
x=8+3×(−2)
x=8−6
x=2
Therefore, x=2 and y=−2
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