Math, asked by ashmita1256, 1 year ago

Solve 3x-5y=20 and 6x-10y=40 by elimination method.

Answers

Answered by akshaym72sl
3

Answer:

Infinite solution.

Given:

3x-5y= 20,

6x-10y= 40

Step-by-step explanation:

First equate the coefficients of y terms of both equations.

3x - 5y= 20,

6x - 10y= 40

we will get,

2(3x - 5y = 20)

6x - 10y = 40

⇒ 6x - 10y = 40

   6x - 10y = 40

As, both equations are same.

so infinite solution.

Hence, system of equations have infinite solution.

#SPJ2

Answered by jenisha145
1

The equations 3x-5y=20 and 6x-10y=40 has infinite solutions

Step-by-step explanation:

Given:

equations are 3x-5y=20 &

6x-10y=40

To find:

solve by elimination method

Solution:

The equations can be solved by the elimination method and for that, we have one like term between the two equations to eliminate.

Let's say 3x-5y=20...............(1)

& 6x-10y=40.................(2)

Multiplying equation (1) by 2 we get

6x-10y=40........(3)

Now subtracting equations (2) & (3) we get

6x- 10y = 40

6x- 10y=  40

(-) (+)      (-)    

        0              

As clearly seen the equations do not have a solution. The result gives us 0.

We can say that equation 3x-5y=20 & 6x-10y=40 has infinite solutions.

#SPJ2

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