Solve 3x-5y=20 and 6x-10y=40 by elimination method.
Answers
Answer:
Infinite solution.
Given:
3x-5y= 20,
6x-10y= 40
Step-by-step explanation:
First equate the coefficients of y terms of both equations.
3x - 5y= 20,
6x - 10y= 40
we will get,
2(3x - 5y = 20)
6x - 10y = 40
⇒ 6x - 10y = 40
6x - 10y = 40
As, both equations are same.
so infinite solution.
Hence, system of equations have infinite solution.
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The equations 3x-5y=20 and 6x-10y=40 has infinite solutions
Step-by-step explanation:
Given:
equations are 3x-5y=20 &
6x-10y=40
To find:
solve by elimination method
Solution:
The equations can be solved by the elimination method and for that, we have one like term between the two equations to eliminate.
Let's say 3x-5y=20...............(1)
& 6x-10y=40.................(2)
Multiplying equation (1) by 2 we get
6x-10y=40........(3)
Now subtracting equations (2) & (3) we get
6x- 10y = 40
6x- 10y= 40
(-) (+) (-)
0
As clearly seen the equations do not have a solution. The result gives us 0.
We can say that equation 3x-5y=20 & 6x-10y=40 has infinite solutions.
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