solve 3x+5y=25,7x+6y=30
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3x+5y = 25 , 7x+6y = 30
Using substitution method :
3x+5y = 25 --------> (i)
7x+ 6y = 30 -------->(ii)
From equation(i)
3x= 25-5y
x = 25-5y/ 3------->(iii)
Putting the value of x in equation (ii)
7x +6y =30
7(25-5y/3) = 30
175 -35y +18y = 90
175 -90 -17y =0
85 -17y =0
-17y = -85
y = 85/ 17
y = 5
Putting value of y in equation (iii)
x= 25-5y /3
x= 25-5(5)/ 3
x= 25-25 / 3
x= 0/3
x = 0
So value of x= 0 and y= 5
Thankss
Hope it helps u☆☆☆
Using substitution method :
3x+5y = 25 --------> (i)
7x+ 6y = 30 -------->(ii)
From equation(i)
3x= 25-5y
x = 25-5y/ 3------->(iii)
Putting the value of x in equation (ii)
7x +6y =30
7(25-5y/3) = 30
175 -35y +18y = 90
175 -90 -17y =0
85 -17y =0
-17y = -85
y = 85/ 17
y = 5
Putting value of y in equation (iii)
x= 25-5y /3
x= 25-5(5)/ 3
x= 25-25 / 3
x= 0/3
x = 0
So value of x= 0 and y= 5
Thankss
Hope it helps u☆☆☆
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