solve: 3x-5y-4=0 and 9x-2y-7=0 by elimination method
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Answered by
7
(3x -5y=4)×2
(9x-2y= 7)×5
6x-10y=8
45-10y= 35
now , subtract.
so , we get
39x= 27
x = 27/39 = 9/13
so , y = -5/13 ans.
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(9x-2y= 7)×5
6x-10y=8
45-10y= 35
now , subtract.
so , we get
39x= 27
x = 27/39 = 9/13
so , y = -5/13 ans.
Mark it as a brainliest
Answered by
2
Answer:
=We have Elimination method
=3x-5y-4=0..... (i)
9x-2y-7=0.......(ii)
=3{3x-5y-4=0}
1{9x-2y-7=0}
= 9x-15y-12=0
9x-2y-7=0
=-13y-5=0
y=-5/13
putting y=-5/13 in (i)
3x-5(-5/13)-4=0
3x+25/13-4=0
3x = 4-25/13
3x= (52-25)/13
x= (27/39)
hence x= 9/13
y=-5/13
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