Solve(3x^+6xy)dx+(6x^y+4y3)Dy=0
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When solving the differential equation
(3x 2+6xy 2)dx+(6x 2y+4y 2)dy=0
I verified that it is an Exact Equation. By saying that
F x=3x 2+6xy 2 F y=6x 2y+4y 2
and integrating both sides I found
F(x,y)=3x 2y 2+4 3y 3+x 3=C
and since
y(0)=2
we have
3x 2y 2+4 3y 3+x 3=32 3
The problem is that the textbook's solution is
x 3+3x 2y 2+y 3=16
Thank you.
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