Solve
3x(7x-4)=(5x-2)(3x4)
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Answered by
3
HEY!!
_______________________________
3x(7x-4) = (5x-2)(3x+4)
▶Expand the both sides :
3x(7x-4) = 5x(3x+4) - 2 (3x+4)
21x2 - 12x = 15x2+ 20x - 6x -8
(21x2 - 15x2) + ( -12x-20x+6x) + 8 = 0
6x2 - 26x +8 = 0
▶Dividing both sides by "2"
3x2 - 13x + 4 = 0
▶By splitting the middle term :
3x2 - 1x-12x + 4 = 0
x(3x-1) -4(3x-1) = 0
(x-4) (3x-1) = 0
x-4 = 0 and 3x-1 = 0
x=4 and x = 1/3
✔The value of x = 4 , 1/3
_______________________________
3x(7x-4) = (5x-2)(3x+4)
▶Expand the both sides :
3x(7x-4) = 5x(3x+4) - 2 (3x+4)
21x2 - 12x = 15x2+ 20x - 6x -8
(21x2 - 15x2) + ( -12x-20x+6x) + 8 = 0
6x2 - 26x +8 = 0
▶Dividing both sides by "2"
3x2 - 13x + 4 = 0
▶By splitting the middle term :
3x2 - 1x-12x + 4 = 0
x(3x-1) -4(3x-1) = 0
(x-4) (3x-1) = 0
x-4 = 0 and 3x-1 = 0
x=4 and x = 1/3
✔The value of x = 4 , 1/3
Answered by
1
Hi friend!!
Given,
Your question should be
3x(7x-4)=(5x-2)(3x+4)
21x²-12x=15x²+20x-6x-8
6x²-26x+8=0
3x²-13x+4=0
3x²-12x-x+4=0
3x(x-4)-1(x-4)=0
(3x-1)(x-4)=0
x=1/3, 4
I hope this will help you ;)
Given,
Your question should be
3x(7x-4)=(5x-2)(3x+4)
21x²-12x=15x²+20x-6x-8
6x²-26x+8=0
3x²-13x+4=0
3x²-12x-x+4=0
3x(x-4)-1(x-4)=0
(3x-1)(x-4)=0
x=1/3, 4
I hope this will help you ;)
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