Math, asked by Anonymous, 5 hours ago

Solve 3x+8>2, when

(i) x is an integer

(ii) x is a real number​

Answers

Answered by TYKE
1

The given inequality is 3x + 8 > 2

3x + 8 > 2

3x > 2 – 8

3x > – 6

x > – 2

The Integers are – 1,0,1,2

ii) When x is a real number the solution is (–2, infinity)

Answered by BrainlyPARCHO
17

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  • (i) x is an integer

Answer → -1, 0, 1, 2

  • (ii) x is a real number

Answer →[-2 , ∞ )

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