solve:√3x(square)2+10x+7√3=0
class: 10th ICSE
Answers
Answered by
0
Answer:
√3x^2+10x+7√3=0
=> √3x^2+7x+3x+7√3=0
=> x(√3x+7)+√3(√3x+7)=0
=> (√3x+7)(x+√3)=0
=> √3x+7=0
=> x= -7/√3
again, x+√3=0
=> x= -√3
Similar questions