Question

solve....

3x+y=5 and 2x+3y =1

Answer 1

Hello friend

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Ans==>

3x + y = 5 ................. (1)

2x - y = 1 ....................(2)


Multiply by 3 equation (1) we get,

9x + 3y = 15 ...................(3)


Now subtracting equation (2) and (3) we get,


9x + 3y = 15

2x + 3y = 1
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7x = 14

x = 14/7

x = 2


Substituting x = 2 in (2) we get

2x + 3y = 1


2 x 2 + 3y = 1

4 + 3y = 1


3y = 1 -4

3y = -3

y = -3/3

y = -1


Therefore, x = 2 and y = -1 are the solution of the given equation.


Thanks...


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Answer 2

Answer:

x = 2, y = -1

Explanation:

The given equations are called as linear equations in two variable.

By solving the equations refers to finding the unknown variables.

There are different methods of solving the equations.Substitution method, Elimination method, Cross multiplication method and equation reducible method.

Elimination Method:

3x + y = 5 eq1

2x +3y = 1 eq2

Here, we may select any one of the variable either x or y and make their coefficients equal first.

(3x + y = 5 ) x 3

9x + 3y = 15 eq

Now subtracting eq 2 and eq 3

9x + 3y = 15

-2x - 3y = - 1

On eliminating

7x + 0 = 14

x = 14/7 = 2

Thus, x= 2.

Now, substitute the x value in any one of the equation.

3x + y = 5

3(2) + y = 5

6 + y = 5

y = 5 - 6 = -1

x = 2, y = -1