Question

Solve √3x2+11x+6√3=0

Answer 1

Answer:

» √3x² + 11x + 6√3 = 0

» √3x² + 9x +2x + 6√3 = 0

» √3x (x + 3√3) + 2 (x + 3√3) = 0

» (√3x + 2) (x + 3√3) = 0

» x = -2/√3 or -3√3

Answer 2

Answer:

$\: \: \frac{8 \sqrt{3} }{11 \: } or \: x = - 1.259$

Step by step explanation :

$\sqrt{3} \times 2 + 11x + 6 \sqrt{3} = 0$

or,

$2 \sqrt{3} + 11x + 6 \sqrt{3} = 0$

or,

$8 \sqrt{3} + 11x = 0$

or,

$11x = - 8 \sqrt{3}$

or,

$x = - \frac{8 \sqrt{3} }{11} or \: 1.25967$