solve √3x²-2√2x-2√3 by factorisation
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2
Answer:
√3 x² - 2√2 x - 2√3 = 0
Multiplying √3 and 2√3 = 6
now, split this in such a way that it's sum of difference will be -2√2
i.e. -3√2 +√2 = -2√2
√3 x²-3√2x +√2x -2√3 =0
=√3x(x -√6) +√2(x -√6) =0
=(x-√6)(√3x +√2) =0
So, (x-√6)=0 or (√3x +√2) =0
x = √6 or x= -√(2/3)= -√6/3
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Step-by-step explanation:
dv791204:
nice
Answered by
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★GOOD MORNING★
√3x² - 3√2x + √2x - 2√3
=>
√3x { x - 3√2/√3 } + √2 ( x - 2√3/√2 )
=>
√3x { x - √6 } + √2 { x - √6 }
=>
{ √3x + √2 } × { x - √6 }
☺️☺️
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