Question

solve √3x²-2√2x-2√3 by factorisation​

Answer 1

Answer:

√3 x² - 2√2 x - 2√3 = 0

Multiplying √3 and 2√3 = 6

now, split this in such a way that it's sum of difference will be -2√2

i.e. -3√2 +√2 = -2√2

√3 x²-3√2x +√2x -2√3 =0

=√3x(x -√6) +√2(x -√6) =0

=(x-√6)(√3x +√2) =0

So, (x-√6)=0 or (√3x +√2) =0

x = √6 or x= -√(2/3)= -√6/3

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Step-by-step explanation:

Answer 2

★GOOD MORNING★

√3x² - 3√2x + √2x - 2√3

=>

√3x { x - 3√2/√3 } + √2 ( x - 2√3/√2 )

=>

√3x { x - √6 } + √2 { x - √6 }

=>

{ √3x + √2 } × { x - √6 }

☺️☺️