Question

solve
3x²+5x+7/10x+14=3x²+4x+3/8x+6​

Answer 1

Answer:

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Step-by-step explanation:

Question 12:

Solve the following: x/3 + 1 = 7/15

Answer:

Given, x/3 + 1 = 7/15

=> x/3 = 7/15 – 1

=> x/3 = (7 - 15)/15 [LCM (15, 1) = 15]

=> x/3 = -8/15

=> x = 3 * (-8/15)

=> x = (-3 * 8)/15

=> x = -24/15

=> x = -8/5 [24 and 15 are divided by 3]

Question 6:

Three consecutive integers add up to 51. What are these integers?

Answer:

Let the three consecutive integers be x x + 1 and x + 2.

According to the question,

x + x + 1 + x + 2 = 51

=> 3x + 3 = 51

=> 3x = 51 – 3

=> 3x = 48

=> x = 48/3

=> x = 16

Hence, first integer = 16, second integer = 16 + 1 = 17 and third integer = 16 + 2 = 18

Question 7:

The sum of three consecutive multiples of 8 is 888. Find the multiples.

Answer:

Let the three consecutive multiples of 8 be x, x + 8 and x +16.

According to question,

x + x + 8 + x + 16 = 888

=> 3x + 24 = 888

=> 3x = 888 – 24

=> 3x = 864

=> x = 864/3

=> x = 288

Hence, first multiple of 8 = 288, second multiple of 8 = 288 + 8 = 296

and third multiple of 8 = 288 + 16 = 304.