Question

solve 3x²+7x+2=0 find roots​

Answer 1

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Answer 2

${3x}^{2} + 7x + 2 = 0 \\ a = 3 \\ b = 7 \\ c = 2 \\ x = \frac{- b±\sqrt{ {b}^{2} - 4ac} }{2a}</p><p>$$\frac{ - 7± {} \sqrt{ {7}^{2} - 4 \times 3 \times 2} }{2 \times 3} = \frac{ - 7± \sqrt{49 - 24} }{6} = \frac{ - 7± \sqrt{25} }{6} = \frac{ - 7±5}{6}$

$x = \frac{ - 7 + 5}{6} = \frac{ - 2}{6} = \frac{ - 1}{3} \\ x = \frac{ - 7 - 5}{6} = \frac{ - 12}{6} = - 2 \\ the \: roots \: are \: \frac{ - 1}{3 } \: and \: - 2$