Solve:-
-3x² + 9/2xy -6xz ÷ -3/2x
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Question
Factorise: 9(2x−y)2−4(2x−y)−13
Let (2x−y)=p, then the equation 9(2x−y)2−4(2x−y)−13 becomes 9p2−4p−13
Consider the expression 9p2−4p−13 we can factorise it as follows:
9p2−4p−13=9p2+9p−13p−13=9p(p+1)−13(p+1)=(9p−13)(p+1)
Now, substitute the value of p as p=(2x−y):
(9p−13)(p+1)=(9(2x−y)−13)(2x−y+1)=(18x−9y−13)(2x−y+1)
Hence, 9(2x−y)2−4(2x−y)−13=(18x−9y−
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