Question

solve 3xcube + 5xsqaure-6x-13 by using division algorthim​

Answer 1

Answer:

Quotient = 3

Remainder = 4x^2

Step-by-step explanation:

Dividend = 3 x^3+ 4 x^2+ 6x + 9

Divisor = 3x^3+2x+3

Dividend = (Divisor\times quotient)+Remainder

3 x^3+ 4 x^2+ 6x + 9 = (3x^3+2x+3 \times 3)+4x^2

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So, quotient = 3

Remainder = 4x^2

To Verify :

3 x^3+ 4 x^2+ 6x + 9 = (9x^3+6x+9)+4x^2

3 x^3+ 4 x^2+ 6x + 9 = 9x^3+6x+4x^2+9

So, LHS = RHS

Hence verified