Math, asked by JAYANTH8231, 11 months ago

Solve 3xsquare-2root6x+2=0 by factorisation

Answers

Answered by devraaz170
0

Answer:

(√3x - √2)(√3x - √2)

Explanation:

3x^2 - 2√6 x +2 =0

=> (√3x)^2 - 2×√3×√2x +(√2)^2=0

=> (√3x - √2)^2

=> (√3x - √2)(√3x - √2)

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