Question

Solve
4√(30×2)3
Solution

Answer 1

Answer

The number of ways of choosing one odd and one even number is

5

C

1

×

5

C

1

=5×5=25

Total number of ways of choosing 2 cards out of 10=

10

C

2

=45

Thus, probability =25/45=5/9

Answer 2

Step-by-step explanation:

4√60×3

4√180

=53.66563146