Question

Solve:4-3x/5+7-x/3+13/3=0. Hence, find the value of 'p', if 3p-2x+1=0​

Answer 1

[tex]\huge{ \mathfrak{{Answer:-} }} \\ \frac{4-3x}{5}+\frac{7-x}{3}+\frac{13}{3}=0 \\\frac{3(4-3x)+5(7-x)+5(13)}{15}=0 \\ \frac{12-9x+35-5x+65}{15}=0\\ \frac{12+35+65-9x-5x}{15}=0\\ \frac{112-14x}{5}=0\\ 112-14x=0×5\\ 112-14x=0\\ 14x=112\\ x=\frac{112}{14}\\ x=8\\ 3p-2x+1=0\\ 3p-2(8)+1=0\\ 3p-16+1=0\\ 3p-15=0\\ 3p=15\\ p=\frac{15}{3}\\ \bold{ \large{ \boxed{p=5} }} [/tex]