Question

Solve:4-3x/5+7-x/3+13/3=0. Hence, find the value of 'p', if 3p-2x+1=0

Answer 1

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Answer 2

The value of p is 5

Step-by-step explanation:

Given :$\frac{4-3x}{5}+\frac{7-x}{3}+\frac{13}{3}=0$

Solution:

$\frac{4-3x}{5}+\frac{7-x}{3}+\frac{13}{3}=0\\\frac{12-9x+35-5x+65}{15}=0\\\frac{112-14x}{15}=0\\\frac{112}{14}=x$

8=x

Now,3p-2x+1=0

So,3p-2(8)+1=0

3p-16+1=0

3p-15=0

p=5

Hence the value of p is 5

#Learn more:

P-(3p-2/3)=2+(p-4)

2x/3 - x/5 = (3x-1/4)​

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