Solve: 4(a+3)=18-2(3-2a)
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Answered by
1
if you replace a=1 then you get,
4(1+3)=18-2(3-2(1))
4(4)=16(3-2)
16=16(1)
...16=16
therefore it is proved !
4(1+3)=18-2(3-2(1))
4(4)=16(3-2)
16=16(1)
...16=16
therefore it is proved !
Answered by
1
here ...here is your answer..
4a +12= 52-36a-6+4a
4a+36a-4a =52 -6 -12
40a -36a =52-18
64a = 34
a. = 34/64
a. =17/32
4a +12= 52-36a-6+4a
4a+36a-4a =52 -6 -12
40a -36a =52-18
64a = 34
a. = 34/64
a. =17/32
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